5x^2+2x+15=3x^2+13x+27

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Solution for 5x^2+2x+15=3x^2+13x+27 equation:



5x^2+2x+15=3x^2+13x+27
We move all terms to the left:
5x^2+2x+15-(3x^2+13x+27)=0
We get rid of parentheses
5x^2-3x^2+2x-13x-27+15=0
We add all the numbers together, and all the variables
2x^2-11x-12=0
a = 2; b = -11; c = -12;
Δ = b2-4ac
Δ = -112-4·2·(-12)
Δ = 217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{217}}{2*2}=\frac{11-\sqrt{217}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{217}}{2*2}=\frac{11+\sqrt{217}}{4} $

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